Question

AYUDAAAAA metodo de sustitucion

4x + 6y = -32
-2x + y = -16

Answer 1

SOLUCIÓN

♛ HØlα!! ✌

                     $Despejaremos\:"x"\:de\:la\:primera\:ecuaci\'on\\\\4x+6y=-32\\\\\\4x=-32-6y\\\\\\x=\dfrac{-32-6y}{4}\\\\\\Reemplazamos\:x\:en\:la\:segunda\:ecuaci\'on\\\\\\-2x+y=-16\\\\\\(-2)\left(\dfrac{-32-6y}{4}\right)+y=-16\\\\\\\dfrac{(-2)(-32-6y)+[(4)(y)]}{4}=-16\\\\\\(64+12y)+(4y)=(-16)(4)\\\\\\64+16y=-64\\\\\\16y=-128\\\\\\y=\dfrac{-128}{16}\\\\\\\boxed{\boldsymbol{y=-8}}$

                     $Reemplazamos\:"y"\:en\:"x"\\\\\\x=\dfrac{-32-6y}{4}\\\\\\x=\dfrac{-32-6(-8)}{4}\\\\\\x=\dfrac{-32+48}{4}\\\\\\x=\dfrac{16}{4}\\\\\\\boxed{\boldsymbol{x=4}}$