Respuestas
Respuesta:
x² - 7 + 3 = 0
x² -4 = 0
ax² + bx + c = 0
a = 1
b = 0
c = -4
Aplicamos formula general
-b+-√b² - 4ac
x = -------------------
2a
- (0)+-√(0)² - 4 · (1) · (-4) 0+-√0 + 16 0+-4 0 + 4 4
x = --------------------------------- = ----------------- = -------- = --------- = ------ = 2
2 · 1 2 2 2 2
0 - 4 -4
------- = ----- = -2
2 2
x = 2
x = -2
Respuesta:
x² - 7 + 3 = 0
x² -4 = 0
ax² + bx + c = 0
a = 1
b = 0
c = -4
Aplicamos formula general
-b+-√b² - 4ac
x = -------------------
2a
- (0)+-√(0)² - 4 · (1) · (-4) 0+-√0 + 16 0+-4 0 + 4 4
x = --------------------------------- = ----------------- = -------- = --------- = ------ = 2
2 · 1 2 2 2 2
0 - 4 -4
------- = ----- = -2
2 2
x = 2
x = -2