Question

¡ayuda en este método por favor! ​

Answer 1

Respuesta:

Explicación paso a paso:

$\left\lbrace\begin{array}{rcl}3x-5y&=-15\\2x+y&=&16\end{array}\right.$

Aplicando la regla de Cramer:

$\Delta=\left|\begin{matrix}3&-5\\2&1\end{matrix}\right|=13\\\\\Delta_{1}=\left|\begin{matrix}15&-5\\16&1\end{matrix}\right|=65\\\\\Delta_{2}=\left|\begin{matrix}3 & -15 \\2 & 16\end{matrix}\right|=78\\\\x=\frac{\Delta_{1}}{\Delta}=5\\\\y=\frac{\Delta_{2}}{\Delta}=6$

$\left\lbrace\begin{array}{rcl}7x+8y&=&-5\\-x+9y&=&21\end{array}\right.\\\\\Delta=\left|\begin{matrix}7&8\\-1&9\end{matrix}\right|=71\\\\\Delta_{1}=\left|\begin{matrix}-5&8\\21&9\end{matrix}\right|=-213\\\\\Delta_{2}=\left|\begin{matrix}7&-5\\-1&21\end{matrix}\right|=142\\\\x=\frac{\Delta_{1}}{\Delta}=-3\\\\y=\frac{\Delta_{2}}{\Delta}=2$

Saludos