Por favor es de urgencia
Respuestas
Se proporcionan tres (3) funciones cada una con dos intervalos diferentes de validez.
Se debe utilizar los intervalos para ingresarlos en la función y obtener los valores respectivos de la misma.
• F(x) = 2x²
Intervalos [– 3; 0] y [1; 2]
F(– 3) = 2(– 3)²
F(– 3) = 2(9)
F(– 3) = 18
F(– 2) = 2(– 2)²
F(– 2) = 2(4)
F(– 2) = 8
F(– 1) = 2(– 1)²
F(– 1) = 2(1)
F(– 1) = 2
F(0) = 2(0)²
F(0) = 0
F(1) = 2(1)²
F(1) = 2(1)
F(1) = 2
F(2) = 2(2)²
F(2) = 2(4)
F(2) = 8
• F(x) = 2x – 1
Intervalos [0; 2] y [4; 5]
F(0) = 2(0) – 1
F(0) = – 1
F(1) = 2(1) – 1
F(1) = 2 – 1
F(1) = 1
F(2) = 2(2) – 1
F(2) = 4 – 1
F(2) = 3
F(4) = 2(4) – 1
F(4) = 8 – 1
F(4) = 7
F(5) = 2(5) – 1
F(5) = 10 – 1
F(5) = 9
• F(x) = x² – x + 3
Intervalos [0; 2] y [4; 5]
F(0) = (0)² – (0) + 3
F(0) = 3
F(1) = (1)² – (1) + 3
F(1) = 1 – 1 + 3
F(1) = 3
F(2) = (2)² – (2) + 3
F(2) = 4 – 2 + 3
F(2) = 5
F(4) = (4)² – (4) + 3
F(4) = 16 – 4 + 3
F(4) = 15
F(5) = (5)² – (5) + 3
F(5) = 25 – 5 + 3
F(5) = 23