Question

Alguien sabe como se hace esto?​

Answer 1

Respuesta:

b) $\frac{3}{2}+\frac{\sqrt{5}}{2}$

e) $\sqrt{2}-1$

Explicación paso a paso:

b)

$\frac{\sqrt{3+\sqrt{5}}}{\sqrt{3-\sqrt{5}}}.\frac{\sqrt{3-\sqrt{5}}}{\sqrt{3-\sqrt{5}}}$

$\frac{\sqrt{9-5}}{3-\sqrt{5}}=\frac{\sqrt{4}}{3-\sqrt{5}}$

$\frac{2}{3-\sqrt{5}}.\frac{3+\sqrt{5}}{3+\sqrt{5}}$

$\frac{2(3+\sqrt{5})}{9-5}=\frac{2(3+\sqrt{5})}{4}$

$\frac{3}{2}+\frac{\sqrt{5}}{2}$

e)

$\frac{\sqrt{2-\sqrt{2}}}{\sqrt{2+\sqrt{2}}}.\frac{\sqrt{2+\sqrt{2}}}{\sqrt{2+\sqrt{2}}}$

$\frac{\sqrt{4-2}}{2+\sqrt{2}}=\frac{\sqrt{2}}{2+\sqrt{2}}$

$\frac{\sqrt{2}}{2+\sqrt{2}}.\frac{2-\sqrt{2}}{2-\sqrt{2}}$

$\frac{2\sqrt{2}-2}{4-2}=\frac{2(\sqrt{2}-1)}{2}$

$\sqrt{2}-1$