Question

log 12(x-3)+log 12(x+1)=1​

Answer 1

Respuesta:

$x=\frac{1+2\log _{10}\left(12\right)}{2\log _{10}\left(12\right)}$

Explicación paso a paso:

$\log _{10}\left(12\right)\left(x-3\right)+\log _{10}\left(12\right)\left(x+1\right)=1\\\\\mathrm{Desarrollar\:}\log _{10}\left(12\right)\left(x-3\right)+\log _{10}\left(12\right)\left(x+1\right):\quad 2\log _{10}\left(12\right)x-2\log _{10}\left(12\right)\\\\2\log _{10}\left(12\right)x-2\log _{10}\left(12\right)=1\\\\2\log _{10}\left(12\right)x=1+2\log _{10}\left(12\right)\\\\x=\frac{1+2\log _{10}\left(12\right)}{2\log _{10}\left(12\right)}$