Question

Hallar la distancia entre p1 (-5,3) y p2 (4,3)
p1 (-4,3) y p2 (3,2)
p1 (4,3) y p2 (-3,-2)
p1 (1,2) y p2 (3,4))

Answer 1

Respuesta:

1) 9.

2) 7.07.

3) 7.07.

4) 2.82.

Explicación paso a paso:

Usamos esta formulas:

$d = \sqrt{(x _{2} - x_{1}) + (y _{2} - y_{2}})$

1)

$d = \sqrt{ (- 5 - 4 {}^{2}) + (3 - 3) {}^{2} }$

$d = \sqrt{ - 9 {}^{2} + 0 {}^{2} }$

$d = \sqrt{81 + 0}$

$d = \sqrt{81}$

$d = 9$

2)

$\sqrt{ (- 4 - 3 {}^{} ) {}^{2} + (3 - 2) {}^{2} }$

$\sqrt{ - 7 {}^{2} + 1 {}^{2} }$

$\sqrt{49 + 1}$

$\sqrt{50}$

$\sqrt{7.07}$

3)

$\sqrt{(4 - ( - 3)) {}^{2} + (3 - 2) {}^{2} }$

$\sqrt{7 {}^{2} + 1 {}^{2} }$

$\sqrt{49 + 1}$

$\sqrt{50}$

$7.07$

2)

$\sqrt{(1 - 3) {}^{2} + (2 - 4) {}^{2} }$

$\sqrt{ - 2 {}^{2} + - 2 {}^{2} }$

$\sqrt{4 + 4}$

$\sqrt{8}$

$2.82$