Question

Hola, disculpen podrían ayudarme a resolver la siguiente suma de vectores analíticamente

a) 60N a 25°
b) 50N a 108°
c) 30N a -205°
d) 80N a -298°
e) 45N a -198°

Answer 1

X=60N(cos.25°)

X=60N(0.906)

X=54.37 N

Y=60N(sen.25°)

Y=60N(0.422)

Y=25.35N

X=50N(cos.108°)

X=50N(-0.309)

X=-15.45N

Y=50N(sen.108°)

Y=50N(0.951)

Y=47.55N

X=30N(cos.-205°)

X=30N(-0.906)

X=-27.189N

Y=30N(sen.-205°)

Y=30N(0.422)

Y=12.67N

X=80N(cos.-298°)

X=80N(0.469)

X=37.55N

Y=80N(sen.-298°)

Y=80N(0.882)

Y=70.63N

X=45N(cos.-198°)

X=45N(-0.951)

X=-42.79N

Y=45N(sen.-198°)

Y=45N(0.309)

Y=13.90N

Sumatoria de X:

Fx=54.37N+(-15.45N)+(-27.189N)+37.55N+(-42.79N)=6.491N

Fy=25.35N+47.55N+12.67N+70.63N+13.90N=170.1N

Vector resultante:

VR²=(6.491N)²+(170.1N)²

VR=√(6.491N)²+(170.1N)²

VR=√42.13N+28934.01N

VR=√28976.14N

VR=170.22N

Arc.tan. =y/x

170.1/6.491=26.2

Tan-¹(26.2)=87.81°