Question

reduce a una sola potencia

a.
${2}^{5} \times 2 {}^{7}$
b.
$( - 2) {}^{3} \times ( + 2) {}^{6}$
c.
$( - 12) {}^{2} \times ( + 12) {}^{2}$
d.
$( + 9) {}^{4} \times ( - 9) {}^{2}$
ayudenme porfabor urjente​

Answer 1

Respuesta:

↓

Explicación paso a paso:

$2^5\cdot \:2^7\\\\\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \:a^b\cdot \:a^c=a^{b+c}\\\\=2^{5+7}\\\\=2^{12}$

$\left(-2\right)^3\cdot \:2^6\\\\\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \:a^b\cdot \:a^c=a^{b+c}\\\\=-2^{3+6}\\\\=-2^9$

$\left(-12\right)^2\cdot \:12^2\\\\=12^2\cdot \:12^2\\\\\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \:a^b\cdot \:a^c=a^{b+c}\\\\=12^{2+2}\\\\=12^4$

$9^4\left(-9\right)^2\\\\=9^4\cdot \:9^2\\\\\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \:a^b\cdot \:a^c=a^{b+c}\\\\=9^{4+2}\\\\=9^6$