Question

1) Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18
with 4.000 moles of O2.
2 C8H18 + 25 02 → 16 CO2 + 18 H20

Answer 1

Respuesta:

25%

Explicación:

equal moles of C8H18 and O2 are reacted to give equal no. of moles of CO2.

mole ratio of C8H18 =(1/2) x 8 = 4 moles

mole ratio of O2 = (1/25) x 4 = 0.16 moles

so, limiting reagent is O2

the no. of moles of CO2 formed = 16 x 0.16 = 2.56 moles

weight of CO2 formed (theoretical weight) = 2.56 x 44 = 112.64

Percentage yield =(practical yiel/theoretical yield) x 100 = (28.16/112.64) x100 = 25%