Question

Como se resuelve las siguientes ecuaciones m+25=38,3b+7=28,4m+5=5,12×-4=6,24m+6=8

Answer 1

Explicación paso a paso:

$1) \\ m + 25 = 38 \\ m = 38 - 25 \\ m = 13\\ \\ 2) \\ 3b + 7 = 28 \\3b = 28 - 7 \\ 3b = 21 \\ b = 21 \div 3 \\ b = 7 \\ \\ 3) \\ 4m + 5 = 5 \\ 4m = 5 - 5 \\ 4m = 0 \\ m = 0 \div 4 \\ m = 0 \\ \\ 4) \\ 12x - 4 = 6 \\ 12x = 6 + 4 \\ 12x = 10 \\ x = \frac{10}{12} \\ \\ x = \frac{5}{6} \\ \\ 5) \\ 24m + 6 = 8 \\ 24m = 8 - 6 \\ 24m = 2 \\ m = 2 \div 24 \\ m = \frac{1}{12}$