Question

78 Halla el resultado de estas operaciones entre fracciones
a ( -10/3+3)×(-3)+1/4
b 1-2:(5/3-7/4)×1/3
c (9/2-1/6):[8+1/3:(-1/2)]
d 6/5×(2/3-1/9):(-3/2+11/4)​

Answer 1

Respuesta:

Explicación paso a paso:

$a)(-\frac{10}{3}+3)*(-3)+\frac{1}{4}  =(\frac{-10+9}{3})*(-3)+\frac{1}{4}  =(-\frac{1}{3})*(-3)+\frac{1}{4}  =\frac{3}{3}+\frac{1}{4}=1+\frac{1}{4}=\frac{4+1}{4}=\frac{5}{4}$

$b)1-2 : (\frac{5}{3} -\frac{7}{4})*\frac{1}{3}=1-2:(\frac{20-21}{12})*\frac{1}{3}  =1-2:(-\frac{1}{12})*\frac{1}{3}=1+24*\frac{1}{3}=1+\frac{24}{3} =1+8=9$

$c)(\frac{9}{2}-\frac{1}{6}):(8+\frac{1}{3}:(-\frac{1}{2}))=(\frac{27-1}{6}):(8+(-\frac{2}{3}))=\frac{26}{6}: (\frac{24-2}{3})=\frac{13}{3}:\frac{22}{3}=\frac{39}{66}=\frac{13}{22}$

$d)\frac{6}{5}*(\frac{2}{3}-\frac{1}{9}):(-\frac{3}{2}+\frac{11}{4})=\frac{6}{5}*(\frac{6-1}{9}):(\frac{-6+11}{4})=\frac{6}{5}*\frac{5}{9}:\frac{5}{4}=\frac{30}{45}:\frac{5}{4}=\frac{120}{225}  =\frac{8}{15}$