Question

Necesito ayuda con estas fracciones la solucion please
1
3_(5/2) 5/4_[7/3_(½)]
2
(5+¼):(⅔)_9/5_(9/2
3
7/4.(5/2)+9/10.(3+⅓)_ 1/3.5
4
(3/2):(⅓_4/9)+5/4.(2+¼)

5. 3
¾+1/5.(2_3/2)++5/2)

Answer 1

Respuesta:

$1) \\ 3 - ( \frac{5}{2} ) \times \frac{5}{4} - ( \frac{7}{3} - (\frac{1}{2})) = \\ \\ \frac{25}{8} - ( \frac{7}{3} - \frac{1}{2} ) = \\ \\ \frac{25}{8} - ( \frac{14 - 3}{6} ) = \\ \\ \frac{25}{8} - \frac{11}{6} = \frac{75 - 44}{24} = \frac{31}{24}$

$2) \\ (5 + \frac{1}{4} ) \div ( \frac{2}{3} ) - \frac{9}{5} - ( \frac{9}{2} ) = \\ \\ (\frac{20 + 1}{4} ) \div - \frac{9}{5} - ( \frac{9}{2} ) = \\ \\ \frac{21}{4} \div \frac{2}{3} - \frac{9}{5} - ( \frac{9}{2} ) = \: \\ \\ \frac{63}{8}- \frac{9}{5} - ( \frac{9}{2} ) = \\ \\ \frac{315 - 72 - 180}{40} = \frac{63}{40}$

$3) \\ \frac{7}{4} \times( \frac{5}{2} ) + \frac{9}{10} \times (3 + \frac{1}{3} ) - \frac{1}{3} \times 5 = \\ \\ \frac{35}{8} + \frac{9}{10} \times ( \frac{9 + 1}{3} ) - \frac{5}{3} \\ \\ \frac{35}{8} + \frac{9}{10} \times \frac{10}{3} - \frac{5}{3} = \\ \\ \frac{35}{8} + \frac{90}{30} - \frac{5}{3} \\ \\ \frac{35}{8} + 3 - \frac{5}{3} = \\ \\ \frac{105 + 72 - 40}{24} = \frac{137}{24}$

$4) \\ ( \frac{3}{2} ) \div ( \frac{1}{3} - \frac{4}{9} ) + \frac{5}{4} \times (2 + \frac{1}{4} ) \\ \\ \frac{3}{2} \div ( \frac{3 - 4}{9} ) + \frac{5}{4} \times ( \frac{8 + 1}{4} ) \\ \\ \frac{3}{2} \div ( - \frac{1}{9} ) + \frac{5}{4} \times \frac{9}{4} = \\ \\ - \frac{27}{2} + \frac{45}{16} = \frac{ - 216 + 45}{16} = - \frac{171}{16}$

$5) \\ \frac{3}{4} + \frac{1}{5} \times (2 - \frac{3}{2} ) + \frac{5}{2} = \\ \\ \frac{3}{4} + \frac{1}{5} \times ( \frac{4 - 3}{2} ) + \frac{5}{2} = \\ \\ \frac{3}{4} + \frac{1}{5} \times ( \frac{1}{2} ) + \frac{5}{2} = \\ \\ \frac{3}{4} + \frac{1}{10} + \frac{5}{2} = \\ \\ \frac{15 + 2 + 50}{20} = \frac{67}{20}$