Question

(b-c)-(6b+8c)=-(10b+5c+3)


(b+c)-(9c-11b)=2c-2b

En metodo de igualacion

Answer 1

Explicación paso a paso:

(b - c) - (6b + 8c) = - (10b + 5c + 3) ......... Ecua(1).

Reducimos los términos semejantes.

b - c - 6b - 8c = - 10b - 5c - 3

- 5b - 9c = - 10b - 5c - 3

5b - 4c = - 3

b = (- 3 +4c)/5 ......... Ecua(1).

......................................................................................................

(b + c) - (9c - 11b) = 2c - 2b

b + c - 9c + 11b = 2c - 2b

12b - 8c = 2c - 2b

14b = 6c     sacamos mitad.

7b = 3c

  b = 3c/7 ...... Ecua(2).

Igualando.

(- 3 + 4c)/5 = 3c/7

7(- 3 + 4c) = 3c(5)

- 21 + 28c = 15c

13c = 21

   c = 21/13

Reemplazando en "Ecua(2)".

b = 3/7 * 13/21

b = 13/49