Question

Calcula el producto de discriminantes de la siguiente ecuación:
(x+3)(x-1)=-3x+4

Answer 1

(x+3)(x-1) = -3x+4

$x^{2}  + 2x - 3 = -3x +4\\\\x^{2} +2x+3x - 3 - 4 = 0\\\\x^{2} +5x -7$

$D = b^{2} - 4ac \\\\D = 5^{2} - 4(1)(-7)\\\\D = 25 + 28\\\\D = 53$

Answer 2

(x+3)(x-1)=-3x+4

(x.x-x + 3x-3)=-3x+4

x2 -x +3x -3x = 4+3

x2 +5x= 7

x2 +2x -3x -7= 0

x2 -x -7 = 0

Ecuación cuadratica

x= -b ± √b2- 4.a.c/2.a

x=5±√5.5 -4.1.-7/2.1

x=5±√25 +28/2

x=5±√53/2

x=5±7,3/2

x=12,3/2

x=6,15

2 es el exponente

a=1

b= -5

c=-7