Question

sin efectuar la multiplicacion haya los productos
(x-y) . (x+y)
(2a-1) . (2a+1)
(1-3ax) . ((1+3ax)
(a-b) . (a+b)
(a-x) . (a+x)
(m+n) . (m-n)
(1/4m+2/5) . (1/4m-2/5n)

Answer 1

Explicación paso a paso:

(x-y) . (x+y) =

${x}^{2} - {y}^{2}$

(2a-1) . (2a+1) =

$4 {a}^{2} - 1$

(1-3ax) . ((1+3ax) =

$1 - 9 {a}^{2} {x}^{2}$

(a-b) . (a+b) =

${a}^{2} - {b}^{2}$

(a-x) . (a+x) =

${a}^{2} - {x}^{2}$

(m+n) . (m-n) =

${ m}^{2} - {n}^{2}$

(1/4m+2/5) . (1/4m-2/5n) =

$(1/16 {m}^{2} -4/25 {n}^{2} )$

espero haberte ayudado. saludos.