Question

AYUDA POR FAVOR

Si sen (3x+20°).csec (x+70°) = 1

Hallar el valor de : √x

Answer 1

sen (3x+20°).csec (x+70°) = 1

3x + 20 = x + 70

3x - x = 70 - 20

2x = 50

x = 50/2

x = 25

$\sqrt{x} = \sqrt{25} = 5$