Question

Hallar X
-3{2[x-(3-2x)]}=-6x-2(4-x)

Answer 1

Explicación paso a paso:

-3{2[x-(3-2x)]}= -6x-2(4-x)

-3{2[x-3+2x)]}= -6x-8+2x

-3{2[3x-3]}= -4x-8

-3{6x-6}= -4x-8

-18x+18= -4x-8

-18x+4x= -8-18

-14x= -26

x=26/14

x=13/7

comprobación

$- 3(2( \frac{13}{7} - (3 - 2 \times \frac{13}{7} ))) = - 6 \times \frac{13}{7} - 2(4 - \frac{13}{7} ) \\ \\ - 3(2( \frac{13}{7} - (3 - \frac{26}{7} ))) = - \frac{78}{7} - 2( \frac{28 - 13}{7} ) \\ \\ - 3(2( \frac{13}{7} - ( \frac{21 - 26}{7} ))) = - \frac{78}{7} - 2( \frac{15}{7} ) \\ \\ - 3(2( \frac{13}{7} - ( - \frac{5}{7} ))) = - \frac{78}{7} - \frac{30}{7} \\ \\ - 3(2( \frac{13}{7} + \frac{5}{7} )) = - \frac{108}{7} \\ \\ - 3(2( \frac{18}{7} )) = - \frac{108}{7} \\ \\ - 3( \frac{36}{7} ) = - \frac{108}{7} \\ \\ - \frac{108}{7} = - \frac{108}{7}$