Question

a projectile is launched with an initial speed of 12 m/s. At its highest point its speed is 6 m/s. What was the launch angle of the projectile?

Answer 1

The launch angle of the projectile is : α  = 60º

   The launch angle of the projectile is calculated with the inclined movement formulas as follows:

Vo = 12m/seg

Vx= 6 m/seg

 α=?

  Vx = Vox = 6 m/seg

   

  Vox = Vo*cosα      ⇒ Cosα  = Vox/Vo

                                     Cos α  = 6m/seg/ 12 m/seg

                                     Cos α = 0.5

                                       α  = cos⁻¹  ( 0.5 )

                                       α = 60º