Question

☆49-14x+x^2
☆4x^2+12x-xy-3y

Answer 1

Respuesta:

${x }^{2} - 14x + 49 = 0 \\ (x -7 )(x - 7) = 0 \\ x = 7 \\ x =$

$4 {x}^{2} + 12x - xy - 3y \\ 4x(x + 3) - y(x + 3) \\ (4x - y)(x + 3)$