Question

[7(3-×)+8(×-4)]-[2-3(×+2)+×]=8​

Answer 1

Respuesta:

5/3

Explicación paso a paso:

[7(3-x)+8(x-4)]-[2-3(x+2)+x]= 8

[21x-7x + 8x-24]- [2-3x+6+x] = 8

21x-7x+8x-24-2+3x-6-x=8

24x - 32 =8

24x = 8+32

24x = 40

x = 40/24 = 20/12 = 10/6 = 5/3

Answer 2

Respuesta:

$(7(3 - x) + 8(x - 4)) - (2 - 3(x + 2) + x) = 8 \\ (21 - 7x + 8x - 32) - (2 - 3x - 6 + x) = 8 \\ - 11 + x - 2 + 3x + 6 - x = 8 \\ - 13 + 6 + 3x = 8 \\ - 7 + 3x = 8 \\ 3x = 8 + 7 \\ 3x = 15 \\ x = 15 \div 3 \\ x = 5$

Explicación paso a paso:

comprobación

$(7(3 - 5) + 8(5 - 4)) - (2 - 3(5 + 2) + 5) = 8 \\ 7\times ( - 2) + 8 \times ( 1) - (2 - 3 \times( 7 )+ 5) = 8 \\ ( - 14) +8 - (2 - 21 + 5) = 8 \\ - 14 + 8 \: - ( - 14 )= 8 \\ - 14 + 8 + 14 = 8 \\ 8 = 8$