Question

(2x-1) (x+1) = 2 [ x+(x+1) (x-1)

Answer 1

(2x-1) (x+1) = 2 [ x+(x+1) (x-1)]2x^2+2x-x-1=2[x+(x^2-x+x-1)]
2x^2+x-1=2[x+(x^2-1)]
2x^2+x-1=2[x+x^2-1]
2x^2+x-1=2x+2x^2-2
2x^2+x-1-2x-2x^2+2=0
-x+1=0 (-1)
x=1