Question

dada la función f(x)=4x+5 determinar
f(2)
f(-4)
f(c)
f(-1)
Si f(x)=x^3-3x-3 determinar
f(1/3)
f(-2)
f(1/b)
f(x+k)

Answer 1

Respuesta:

f(2) = 13

f(-4) = -11

f(c) = 4c + 5

f(-1) = 1

f(1/3) = -107/27

f-2) = -5

f(1/b) = 1/b´3 - 3/b -3

f(x+k) = x´3 + 3*x´2*k + 3*x*k´2 + k3 -3*x - 3*k - 3

Explicación paso a paso:

para f(x)=4x + 5

f(2) = 4*2 + 5 =8+5=13

f(-4)= 4*(-4)+5 =-16 + 5 = -11

f(c)= 4c + 5

f(-1)= 4(-1) + 5 = -4 + 5 =1

para f(x) = x´3 - 3x -3

f(1/3) = (1/3)´3 -3*(1/3) - 3  =1/27 -1 - 3 = 1/27 - 4 = 1 - 27*4      = 1 -108  = -107/27

                                                                                 27                 27

f-2) = (-2)´3 - 3*(-2) -3 = -8 + 6 - 3 = -5

f(1/b) = (1/b)´3 - 3*1/b - 3 = 1/b´3 - 3/b -3

f(x+k) = (x+k)´3 -3*(x+k) - 3

          =x´3 + 3*x´2*k + 3*x*k´2 + k3 -3*x - 3*k - 3