Question

Como resolveria esta ecuación?

Answer 1

3{[(x-2)+4x] -(x-3)} = 4 -(x-12)

3{[x-2+4x] -x+3} = 4 -x+12

3{-2+5x -x+3} = 16-x

3{4x +1} = 16-x

12x+3= 16-x

13x= 16-3

13x= 13

x= 1