Question

Racionalizar el denominador.

Answer 1

Respuesta:

Explicación paso a paso:

$\dfrac{m^2y^3}{\sqrt[4]{8a^3x^2}}=\dfrac{m^2y^3}{(8a^3x^2)^{\frac{1}{4}}}*\dfrac{(8a^3x^2)^4}{(8a^3x^2)^4}=\dfrac{(m^2y^3)(8a^3x^2)^4}{(8a^3x^2)^{\frac{1}{4}}(8a^3x^2)^4}=\dfrac{8^4a^{12}m^2x^8y^3}{{8a^3x^2}}\\\\\\\boxed{\dfrac{m^2y^3}{\sqrt[4]{8a^3x^2}}=8^3a^9m^2x^6y^3}}$

 

$\dfrac{2x^2}{4\sqrt[7]{x^3}}=\dfrac{x^2}{2x^{\frac{3}{7}}}*\dfrac{x^{\frac{7}{3}} }{x^{\frac{7}{3}}}=\dfrac{(x^2)(x^{\frac{7}{3}})}{2(x^{\frac{3}{7}})(x^{\frac{7}{3}})}=\dfrac{x^{\frac{13}{3}} }{2x}\\\\\\\boxed{\dfrac{2x^2}{4\sqrt[7]{x^3}}=\frac{1}{2}x^{\frac{10}{3}}}$