Question

integral de x^2 +4x+1 /(x^2-1)(x+3)

Answer 1

x²+4x+1 ÷(x²-1)(x+3)

x²+4x+ (1 /x²-1).(x+3)

x²+4x+ (x+3)÷(x²-1)

[x². (x²-1)+4x.(x²-1)+x+3] / (x²-1)

(x^4-x²+4 x³ -4x+x+3) / ( x²-1 )

(x^4 +4 x³ -x²-3x+3) / (x²-1 )

Espero que entiendas, y te sirva! Besos