si: x+1/x= 3 hallar: x^3+1/x^3​

Respuestas

Respuesta dada por: roycroos
13

SOLUCIÓN

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⚠ Recordemos que

                \boxed{\boldsymbol{(a+b)^3 = a^3 +b^3+3ab(a+b)}}

Entonces

                                     x+\dfrac{1}{x} = 3\\\\\\\left(x+\dfrac{1}{x}\right)^3 = (3)^3\\\\\\x^3+\left(\dfrac{1}{x}\right)^3+3\underbrace{(x)\left(\dfrac{1}{x}\right)}_{1}\underbrace{\left(x+\dfrac{1}{x}\right)}_{3}=3^3\\\\\\x^3+\dfrac{1}{x^3}+ 3(1)(3) = 3^3\\\\\\x^3+\dfrac{1}{x^3}+ 9 = 27\\\\\\\boxed{\boxed{\boldsymbol{x^3+\dfrac{1}{x^3}= 18}}}

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