• Asignatura: Baldor
  • Autor: leyhamjosue
  • hace 8 años

algebra ejercicio 80 resueltos

Respuestas

Respuesta dada por: superg82k7
69

Del libro de texto "Álgebra" del Profesor Aurelio Baldor se revuelven algunos de los problemas del  ejercicio 80.

1) x + 3(x - 1) = 6 – 4(2x + 3)

x + 3x – 3 = 6 – 8x – 12

4x – 3 = - 8x – 6

12x = - 3

X = - 3/12

X = - 1/4

2) 5(x – 1) + 12(2x + 3) = 3(2x - 7)

5x – 5 + 32x + 48 = 6x – 21 – x

37x + 43 = 5x – 21

37x – 5x = - 21 – 43

32x = - 64

X = - 64/32

X = - 2

3) 2(3x + 3) – 4(5x - 3) = x(x – 3) – x(x + 5)

6x + 6 – 20x + 12 = x² – 3x – x² – 5x

-14x + 18 = - 8x

-14x + 8x = - 18

-6x = - 18

X = - 18/- 6

X = 3

4) 184 – 7(2x + 5) = 301 + 6(x – 1) – 6

184 – 14x – 35 = 301 + 6x – 6 – 6

149 – 14x = 289 + 6x

149 – 289 = 6x + 14x

-140 = 20x

X = - 140/20

X = - 7

5) 7(18 – x) – 6(3 – 5x) = - (7x + 9) – 3(2x + 5) - 12

126 – 7x – 18 + 30x = - 7x – 9 – 6x – 15 – 12

23x + 108 = – 13x – 36

23x + 13x = - 36 - 108

36x = - 144

X = - 144/36

X = 4

6) 3x(x – 3) + 5(x + 7) – x(x + 1) – 2(x2 + 7) + 4 = 0

3x² – 9x + 5x + 35 – x² – x – 2x² – 14 + 4 = 0

-5x + 25 = 0

-5x = - 25

X = - 25/ -5

X = 5

7) -3(2x + 7) + (- 5x + 6) – 8(1 – 2x) – (x – 3) = 0

-6x – 21 – 5x + 6 – 8 + 16x – x + 3 = 0

4x – 20 = 0

4x = 20

X = 20/4

X = 5

8) (3x – 4)(4x - 3) = (6x - 4)(2x – 5)

12x² – 9x – 16x + 12 = 12x² – 38x + 20

-25x + 38x = 20 – 12

13x = 8

X = 8/13

9) (4 – 5x )(4x - 5) = (10x - 3)(7 – 2x)

-20x² + 41x  - 20 = - 20x² + 76x – 21

41x – 76x = - 21 + 20

-35x = - 1

X = - 1/- 35

X = 1/35

10) (x + 1)(2x + 5) = (2x + 3)(x - 4) + 5

2x² + 7x + 5 = 2x² – 5x – 12 + 5

7x + 5x = - 7 - 5

12x = - 12

X = - 12/12

X = - 1

11) (x – 2)² – (3 –x )² = 1

x² – 4x + 4 – 9 + 6x – x² = 1

2x – 5 = 1

2x = 6

X = 6/2

X = 3

El resto de los ejercicios se dejan par que el interesado los resuelva y fije de ese modo los conocimientos en el tema.


maydelinpor: grasias
Respuesta dada por: npalaciosjijon
28

Respuesta:

1) x + 3(x - 1) = 6 – 4(2x + 3)

x + 3x – 3 = 6 – 8x – 12

4x – 3 = - 8x – 6

12x = - 3

X = - 3/12

X = - 1/4

2) 5(x – 1) + 12(2x + 3) = 3(2x - 7)

5x – 5 + 32x + 48 = 6x – 21 – x

37x + 43 = 5x – 21

37x – 5x = - 21 – 43

32x = - 64

X = - 64/32

X = - 2

3) 2(3x + 3) – 4(5x - 3) = x(x – 3) – x(x + 5)

6x + 6 – 20x + 12 = x² – 3x – x² – 5x

-14x + 18 = - 8x

-14x + 8x = - 18

-6x = - 18

X = - 18/- 6

X = 3

4) 184 – 7(2x + 5) = 301 + 6(x – 1) – 6

184 – 14x – 35 = 301 + 6x – 6 – 6

149 – 14x = 289 + 6x

149 – 289 = 6x + 14x

-140 = 20x

X = - 140/20

X = - 7

5) 7(18 – x) – 6(3 – 5x) = - (7x + 9) – 3(2x + 5) - 12

126 – 7x – 18 + 30x = - 7x – 9 – 6x – 15 – 12

23x + 108 = – 13x – 36

23x + 13x = - 36 - 108

36x = - 144

X = - 144/36

X = 4

6) 3x(x – 3) + 5(x + 7) – x(x + 1) – 2(x2 + 7) + 4 = 0

3x² – 9x + 5x + 35 – x² – x – 2x² – 14 + 4 = 0

-5x + 25 = 0

-5x = - 25

X = - 25/ -5

X = 5

7) -3(2x + 7) + (- 5x + 6) – 8(1 – 2x) – (x – 3) = 0

-6x – 21 – 5x + 6 – 8 + 16x – x + 3 = 0

4x – 20 = 0

4x = 20

X = 20/4

X = 5

8) (3x – 4)(4x - 3) = (6x - 4)(2x – 5)

12x² – 9x – 16x + 12 = 12x² – 38x + 20

-25x + 38x = 20 – 12

13x = 8

X = 8/13

9) (4 – 5x )(4x - 5) = (10x - 3)(7 – 2x)

-20x² + 41x  - 20 = - 20x² + 76x – 21

41x – 76x = - 21 + 20

-35x = - 1

X = - 1/- 35

X = 1/35

10) (x + 1)(2x + 5) = (2x + 3)(x - 4) + 5

2x² + 7x + 5 = 2x² – 5x – 12 + 5

7x + 5x = - 7 - 5

12x = - 12

X = - 12/12

X = - 1

11) (x – 2)² – (3 –x )² = 1

x² – 4x + 4 – 9 + 6x – x² = 1

2x – 5 = 1

2x = 6

X = 6/2

X = 3

Explicación:

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