Question

(x+3)²=2(x-3)+36 ayudenme porfa

Answer 1

Explicación paso a paso:

(x+3)^2=2(x-3)+36

x^2+9+6x=2x-6+36

x^2+6x-2x+9+6-30=0

x^2+4x-15=0

$\frac{ - 4 \sqrt{4 {}^{2} - 4 \times 1 \times ( - 15) } }{2 \times 1}$

$\frac{ - 4 + 2 \sqrt{19} }{2} \\ \\ \frac{ - 4 - 2 \sqrt{19} }{2}$

$\frac{ - 2 \sqrt{19} }{2} = - 1 \sqrt{19}$

$\frac{ - 6 \sqrt{19} }{2} = - 3 \sqrt{19}$