Question

Quien me puede ayudar en ese ejercicio ​

Answer 1

Respuesta:

$-\dfrac{3}{10}- \left[\dfrac{7}{5}-\left(\dfrac{5}{6}-\dfrac{2}{3}\right)\right]+4=\bold{\dfrac{37}{15}}$

Explicación paso a paso:

$-\dfrac{3}{10}- \left[\dfrac{7}{5}-\left(\dfrac{5}{6}-\dfrac{2}{3}\right)\right]+4= \\\\Resolvemos\ los\ parentesis\\\\\\-\dfrac{3}{10}- \left[\dfrac{7}{5}-\left(\dfrac{5}{6}-\dfrac{4}{6}\right)\right]+4=\\\\\\-\dfrac{3}{10}- \left[\dfrac{7}{5}-\dfrac{1}{6}\right]+4=\\\\ Ahora \ resolvemos\ los\ corchetes\\\\\\-\dfrac{3}{10}- \left[\dfrac{42}{30}-\dfrac{5}{30}\right]+4=\\\\\\-\dfrac{3}{10}- \dfrac{37}{30}+4=\\\\Resolvemos\ la \ resta\ y \ la \ suma$

$-\dfrac{3}{10}- \dfrac{37}{30}+4=\dfrac{-9-37+120}{30}=\boxed{\bold{\frac{74}{30}=\frac{37}{15}}}$

Espero que te sirva, salu2!!!!