Question

7(x+9)\5+6(2x-7)<7(3x+6)/30+1/2 inecuaciones lineales​

Answer 1

=$\frac{7x+63}{5}+12x-7<\frac{21x+42}{30}+\frac{1}{2}$

=$\frac{67x+28}{5}<\frac{21x+57}{30}$

=$67x+28<\frac{21x+57}{6}$

=$402x+168<21x+57$

=381x<-111

=0.29