Question

A
$2.x + {5}^{2} = 8.7 + {13}^{0}$
B
$7.(x + 4) = 49$
C
$(9.x - 81) \div 3 = \sqrt{4 + 5}$
POR FAVOR AYUDAAA​

Answer 1

Solución:

1)

$2x + {5}^{2} = 8 \times 7 + {13}^{0} \\ 2x + 25 = 56 + 1 \\ 2x + 25 = 57 \\ 2x = 57 - 25 \\ 2x = 32 \\ x = \frac{32}{2} \\ x = 16$

2)

$7(x + 4) = 49 \\ 7x + 28 = 49 \\ 7x = 49 - 28 \\ 7x = 21 \\ x = \frac{21}{7} \\ x = 3$

3)

$(9x - 81) \div 3 = \sqrt{4 + 5} \\ 3x - 27= \sqrt{9} \\ 3x - 27 = 3 \\ 3x = 3 + 27 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10$