Question

$\frac{2}{3} x + 1 = 1.5 - \frac{1}{6}$
ayudita :'( con esta ecuación xfa!!
solo hay que hallar el valor de x...​

Answer 1

$\frac{2}{3} x + 1 = 3.5 - \frac{1}{6} \\\\\frac{2}{3} x = 1.5 - 1 - \frac{1}{6} \\\\\frac{2}{3}x = 0.5- \frac{1}{6}\\\\\frac{2}{3}x = \frac{1}{2} - \frac{1}{6}\\\\\frac{2}{3}x =\frac{6 - 2}{12}\\\\\frac{2}{3}x =\frac{4}{12}\\\\\frac{2}{3}x =\frac{4}{12}\\\\2x =\frac{4}{12}*3\\\\2x =\frac{12}{12}\\\\2x =1\\\\x = 1/2\\\\x = 1/2$

Answer 2

Respuesta:

o

$\frac{2}{3} x + 1 = 1.5 - \frac{1}{6} \\ \\ \frac{2}{3} x + 1 = \frac{15}{10} - \frac{1}{6} \\ \\ \frac{2}{3} x = \frac{15}{10} - \frac{1}{6} - 1 \\ \\ \frac{2}{3} x = \frac{45 - 5 -30 }{30} \\ \\ \frac{2}{3} x = \frac{10}{30} \\ \\ x = \frac{10}{30} \div \frac{2}{3} \\ \\ x = \frac{30}{60} \: simplificamos \: y \: queda \\ \\ x = \frac{3}{6} \: volvemos \: a \: simplificar \: y \: \\ queda \: x = \frac{1}{3}$

$comprobacion \\ \frac{2}{3} \times \frac{1}{3} + 1 = \frac{15}{10} - \frac{1}{6} \\ \\ \frac{3}{9} + 1 = \frac{45 - 5}{30} \\ \\ \frac{3 + 9}{9} = \frac{40}{30} \\ \\ \frac{12}{9} = \frac{4}{3} \\ \\ \frac{4}{3} = \frac{4}{3}$