Question

Ayuda!! Resolver esta ecuacion 2do grado

$<var>\frac{240}{x}=\frac{240}{x+3}+4</var>$

Answer 1

eliminando denominadores tenemos

4x2+12x-720=0

x2+3x-180

(x-12)(x+15)=0

x=12

x=-15

Answer 2

 

 

 

$<var>\frac{240}{x} = \frac{240}{x+3} + \frac{4(x+3)}{x + 3}</var>$

 

$<var>\frac{240}{x} = \frac{240 + 4(x+3)}{x+3} </var>$

 

( 240 )( x + 3 )  = 240x + 4x( x + 3 )

 

240x + 720 = 240x + $<var>4x^2</var>$ + 12x 

 

 

$<var>4x^2 + 12x -720 = 0 </var>$ 

 

dividimos entre 4 

 

$<var>x^2 + 3x - 180 = 0 </var>$

 

 (x + 15) (x  - 12) = 0

 

x = -15  ;   x = 12