Question

realizar las operaciones A. 13/58 + 11/4 - 4 3/10 B. 23/15 + 7/4 - 56 C 5/7 + (7/14 - 3/10) D. ( 9 + 5/9) - (3 1/6 - 2) E. 6/7 + (9/14 - 3/10) + 2 F. 6/7 + 32 4/5 - 4 1/2 H. 4 2/7 + 3/4 - (3 3/10 - 2)

Answer 1

Explicación paso a paso:

a)

$\frac{13}{58} + \frac{11}{4} - \frac{43}{10} = \frac{130 + 1595 - 2494}{580} = - \frac{769}{580}$

b)

$\frac{23}{10} + \frac{7}{4} - 56 = \frac{92 + 105 - 3360}{60} = - \frac{3163}{60}$

c)

$\frac{5}{7} + ( \frac{7}{14} - \frac{3}{10} ) = \\ \\ \frac{5}{7} + ( \frac{70 - 42}{140} ) \\ \\ \frac{5}{7} + \frac{28}{140} = \frac{100 + 28}{140} = \frac{128}{140} \\ simplificamos \: y \: nos \: queda \: \frac{32}{35}$

d)

$(9 + \frac{5}{9} ) - ( \frac{31}{6} - 2) = \\ \\ ( \frac{81 + 5}{9}) - ( \frac{31 - 12}{6} ) = \\ \\ \frac{86}{9} - \frac{19}{6} = \frac{516 - 171}{54} = \frac{345}{54} \\ simplificamos \: y \: nos \: queda \: \frac{115}{18}$

e)

$\frac{6}{7} + ( \frac{9}{14} - \frac{3}{10} ) + 2 = \\ \\ \frac{6}{7} + ( \frac{90 - 42}{140} ) + 2 = \\ \\ \frac{6}{7} + \frac{48}{140} + 2 = \\ \\ \frac{120 + 48 + 280}{140} = \frac{448}{140} \\ simplificó \: y \: nos \: queda \: \frac{16}{5}$

f)

$\frac{6}{7} + \frac{324}{5} - \frac{41}{2} = \frac{60 + 4536 - 1435}{70} = \frac{3161}{70}$

h)

$\frac{42}{7} + \frac{3}{4} - ( \frac{33}{10} - 2) = \\ \\ (\frac{168 + 21}{28} ) - ( \frac{33 - 20}{10} ) = \\ \\ \frac{189}{28} - \frac{13}{10} = \frac{945 - 182}{140} = \frac{763}{140} \\ simplificó \: y \: nos \: queda \: \frac{109}{20}$