Question

AYUDENME A RESOLVER
$\sqrt[3]{x \times 2 = 8}$
$\sqrt{x \div 3 = 6}$
${x}^{3} + 2 = 66$
${x}^{2} - 7 = 18$
SON ECUACIONES ES URGENTE​

Answer 1

1.-

$\sqrt[3]{x \times 2} = 8 \\ \sqrt[3]{2x} = 8 \\ 2x = {8}^{3} \\ 2x = 512 \\ x = \frac{512}{2} \\ x = 256$

2.-

$\sqrt{x \div 3} = 6 \\ \sqrt{ \frac{x}{3} } = 6 \\ \frac{x}{3} = {6}^{2} \\ \frac{x}{3} = 36 \\ x = 36 \times 3 \\ x = 108$

3.-

${x}^{3} + 2 = 66 \\ {x}^{3} = 66 - 2 \\ {x}^{3} = 64 \\ x = \sqrt[3]{64} \\ x = 4$

4.-

${x}^{2} - 7 = 18 \\ {x}^{2} = 18 + 7 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5$