Question

Necesito ayuda en resolver estas ecuaciones con procedimiento

7(x + 8) = -7
5(2x -5) = -25
6(3x -2) =24
9(3x- 7) =18
4(x -9 )=-16
2(X +8) = 40 – X
3 (2X- 5)= 45+4 X
3(8X-2) = 4x-6
4(x-2) = 12 - x

Answer 1

Explicación paso a paso:

$7(x + 8) = - 7 \\ 7x + 56 = - 7 \\ 7x = - 7 - 56 \\ 7x = - 63 \\ x = - 63 \div 7 \\ x = 9$

$5(2x - 5) = - 25 \\ 10x - 25 = - 25 \\ 10x = - 25 + 25 \\ 10x = 0 \\ x = 0 \div 10 \\ x = 0$

$6(3x - 2) = 24 \\ 18x - 12 = 24 \\ 18x = 24 + 12 \\ 18x = 36 \\ x = 36 \div 18 \\ x = 2$

$9(3x - 7) = 18 \\27x - 63 = 18 \\ 27x = 18 + 63 \\ 27x = 81 \\ x = 81 \div 27 \\ x = 3 \\ \\ 4(x - 9) = - 16 \\4x - 36 = - 16 \\ 4x = - 16 + 36 \\ 4x = 20 \\ x = 20 \div 4 \\ x = 5$

$2(x + 8) = 40 - x \\2x + 16 = 40 - x \\ 2x + x = 40 - 16 \\ 3x = 24 \\ x = 24 \div 3 \\ x = 8 \\ 3(2x - 5) = 45 + 4x \\ 6x - 15 = 45 + 4x \\ 6x - 4x = 45 + 15 \\ 2x = 60 \\ x = 60 \div 2 \\ x = 30$

$3(8x - 2) = 4x - 6 \\ 24x - 6 = 4x - 6 \\ 24x - 4x = - 6 + 6 \\ 20x = 0 \\ x = 0 \div 20 \\ x = 0 \\ \\ 4(x - 2) = 12 - x \\ 4x - 8 = 12 - x \\ 4x + x = 12 + 8 \\ 5x = 20 \\ x = 20 \div 5 \\ x = 4$