Question

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Answer 1

$\sqrt[5]{3x + 2} + 4 = 6 \\ \sqrt[5]{3x + 2} = 6 - 4 \\ \sqrt[5]{3x + 2} = 2 \\ {3x + 2} = {2}^{5} \\ 3x + 2 = 32 \\ 3x = 32 - 2 \\ 3x = 30 \\ x = \frac{30}{3} \\ x = 10$