Question

Halla ela area de un trapecio cuya base menor mide 12m la base mayor 7/4 de la menor y su altura 8 m.

Answer 1

$Base\:menor\\b = 12m \\Altura\\ h = 8m \\ Base\:mayor\\B = \frac{7}{4} b = \frac{7}{4}12m = \frac{84m}{4} = 21m$

Area trapecio

$A= \frac{(B + b)h}{2 } \\ A = \frac{(21m + 12m)8m}{2} \\ A = \frac{(33m)8m}{2} \\ A = \frac{264 {m}^{2} }{ 2 } \\A = 132 {m}^{2}$

R) el área del trapecio es de 132m^2