Question

$\frac{4^{-2} }{3} } + 2^{-3} - \frac{3}{4\\}$

Answer 1

$\frac{\frac{1}{16} }{3} +\frac{1}{8}-\frac{3}{4}$

= $\frac{1}{48}+\frac{1}{8}-\frac{3}{4}$

= $\frac{1+6-36}{48}$

= -29/48