Question

Es del tema Segmentos (Geometría) ... ayudenme! es urgente :(

Answer 1

Hola!

Planteando:

AB = 3k

CD = 2k

BC = 6 cm

AB/BC =AD/CD

3k/6 = (3k + 6 + 2k)/2k

k/2 = (5k + 6)/2k

k^2 = 5k + 6

k^2 - 5k = 6

k (k - 5) = 6

=> k = 6

Si "k = 6", entonces:

AD = AB + BC + CD

$AD =3k + 6 cm + 2k \\ AD = 5k + 6cm \\ AD = 5(6) + 6cm \\ AD = 36cm$