si se deja caer libremente un objeto en la luna y en Júpiter Determine la velocidad que alcanzará y la distancia que caerá al cabo de 5 seg . gL=gt/6 gj=80.T
Respuestas
Las velocidades y las distancias alcanzadas por un objeto son :
Vfl 8.165m/s Vfj = 3920m/s hL = 20.41m hJ = 9800m
Para calcular los valores de velocidad y distancia alcanzada por un objeto que se deja caer en la Luna y en Júpiter se debe aplicar las ecuaciones de caída libre como se muestra a continuación :
Vo = O
Vfl = ? velocidad final de la luna
Vfj = ? velocidad final de júpiter
hL = ? altura de la luna
hJ = ? altura de júpiter
t = 5s
gL = gt/6 = 9.8m/s²/6 = 1.633m/s²
gj = 80*gt = 80*90m/s² = 784m/s²
aplicando las ecuaciones de caída libre tenemos :
Vfl = gL*t ⇒ Vfl = 1.633m/s²*5s ⇒ Vfl 8.165m/s
Vfj = gj*t ⇒ Vfj = 784m/s²*5s ⇒ Vfj = 3920m/s
hallando las distancias tenemos :
hL = g*t²/2 ⇒ hL = 1.633m/s²*( 5s)²/2 ⇒ hL = 20.41m
hJ = g*t²/2 ⇒ hJ = 784m/s²*(5s)²/2 ⇒ hJ = 9800m
Respuesta:
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Explicación: