×-[3×-(2×-1)-4(3×-2)=6×​

Respuestas

Respuesta dada por: CSamy
0

×-[3×-(2×-1)-4(3×-2)] = 6×​

×-[3×-(2×-1)-12×+8)] = 6×​

×-[3×-2x+1-12×+8)] = 6×​

×-[x-12×+8+1)] = 6×​

×-[-11×+9] = 6×​

x+11x-9 = 6x

12x - 9 = 6x

12x-6x = 9

6x = 9

x = 9/6

Simplificando sale:

x = 3/2

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