Question

SI TANGENTE β: 0,25
CALCULA E: Senβ+Cosβ ÷ Cscβ+Secβ

Answer 1

tanβ=1/4

entonces:

senβ= 1/√17

cosβ=4/√17

cscβ=√17/1

secβ= √17/4

piden:

senβ+cosβ/cscβ+secβ

=$\frac{\frac{1}{\sqrt{17} }+\frac{4}{\sqrt{17} }}{\frac{\sqrt{17} }{1}+\frac{\sqrt{17} }{4} }$

=$\frac{\frac{5\sqrt{17} }{17} }{\frac{5\sqrt{17} }{4} }$

= 4/17

espero que te ayude :)