Question

Sabiendo que log5 = 0 698, log7=0.845 y log 3= 0.4771.
Encuentra:
A)Log 35
B)Log 5/7
C)Log √21
D)Log Log3/Log5

AYUDA!!!

Answer 1

log(35) = 1.543, log(5/7) = 0.147, Log √21 = 0.66105, Log Log3/Log5 = -0.1658

Algunas propiedades de la función logaritmo son:

$log(a*b) = log(a)+log(b)$

$log(a/b) = log(a)-log(b)$

$log(a^{n}) = n*log(a)$

A)Log 35

log(35)= log(7*5) = log(7)+log(5) = 0.845+0.698 = 1.543

B)Log 5/7

log(7/5) = log(7)-log(5)= 0.745-0.698= 0.147

C)Log √21

$log(\sqrt{21})= log(21^{1/2} ) = log (21^{0.5} ) = 0.5*log(21) =  0.5*(log(7*3))$

$= 0.5*(log(7)+log(3))= 0.5*(0.845+0.4771) = 0.5*1.3221 = 0.66105$

D)Log Log3/Log5

En este ultimo si es necesario realizar un calculo:

$log(\frac{log(3)}{log(5)} )= log(\frac{0.4771}{0.698} )= log(0.6287) = -0.1658$