Question

ayuuuuuuuuuuuuuuuuuuuuudaaaaaaaaaaaaaaaaaaaaaaaa x2=2x(x-1)(x+2) respuesta
formula general

Answer 1

Hola aqui va la respuesta:

${x}^{2} = 2x \times (x - 1)(x + 2)$

${x}^{2} = 2x \times ( {x}^{2} + 2x - x - 2)$

${x}^{2} = 2x \times ( {x}^{2} + x - 2)$

${x}^{2} = 2 {x}^{3} + 2 {x}^{2} - 4x$

${x}^{2} - 2 {x}^{3} - 2 {x}^{2} + 4x = 0$

$- 2 {x}^{3} - {x}^{2} + 4x = 0$

$- x (2 {x}^{2}) - x \times x - x \times 4 = 0$

$- x(2 {x}^{2} + x) - x \times 4 = 0$

$- x(2 {x}^{2} + x - 4) = 0$

$- x \times - 1 = 0$

$1x = 0$

$x = 0$

$2 {x}^{2} + x - 4 = 0$

$\frac{ - b \: ± \: \sqrt{ {b }^{2} - 4 \times a \times c} }{2 \times a}$

$\frac{ - 1 \: ± \: \sqrt{1 - 4 \times 2 \times ( - 4)} }{4}$

$\frac{ - 1 \: ± \: \sqrt{33} }{4}$

$X1 = \frac{ - 1 + \sqrt{33} }{4}$

$X2 = \frac{ - 1 - \sqrt{ 33} }{4}$

Saludoss

Answer 2

${x}^{2} = 2x(x - 1)(x + 2) \\ \frac{ {x}^{2} }{2x} = (x - 1)(x + 2) \\ \frac{x}{2} = {x}^{2} + 2x - x - 2 \\ \frac{x}{2} = {x}^{2} + x - 2 \\ x = 2( {x}^{2} + x - 2) \\ x = 2 {x}^{2} + 2x - 4 \\ 2 {x}^{2} + 2x - 4 - x = 0 \\ 2 {x}^{2} + x - 4 = 0$

Aquí usamos la fórmula general para hallar las dos soluciones:
$\boxed{ \frac{ - b \pm \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} }$
Evaluando obtenemos que:

x1 = 1,18
x2 = -1,68