Question

halle x en -2π, -1π, 2π, 6π, 12π, 19π, x

Answer 1

Tarea

Halle el angulo x en: -2π, -1π, 2π, 6π, 12π, 19π.

Hola!!!

Sabemos que π = 180°

-2π = -2 × 180° ⇒

x = -360°

-1π = -1 × 180°  ⇒

x = -180°

2π = 2 × 180°  ⇒

x = 360°

6π = 6 × 180°  ⇒

x = 1080°

12π = 12 × 180°  ⇒

x = 2160°

19π = 19 × 180°  ⇒

x = 3420°

Saludos!!!