Question

resuelve los sgtes. problemas
1)2√64+36
2)2√64+√36
3)3√48 : 6√12
4)√3+√243+√192+√507

Answer 1

$1) 2 \sqrt{64}+36=2(8)+36=16+36=52 2) 2 \sqrt{64}+ \sqrt{36}=2(8)+6=16+6=22 .$

$3) \frac{3\sqrt{48}}{6\sqrt{12}}= \frac{1}{2} \sqrt{ \frac{48}{12} }= \frac{1}{2} \sqrt{ 4}= \frac{1}{2}2=1 4) \sqrt{3} + \sqrt{(81)(3)}+ \sqrt{(64)(3)}+ \sqrt{(169)(3)} = \sqrt{3} + \sqrt{(81)(3)}+ \sqrt{(64)(3)}+ \sqrt{(169)(3)}= \sqrt{3}+ \sqrt{81}\sqrt{3} + \sqrt{64}\sqrt{3} +\sqrt{169}\sqrt{3} =\sqrt{3}+9\sqrt{3}+8\sqrt{3}+13\sqrt{3} =31\sqrt{3}$