Question

si n(A') =40,n(U)=60y n(Aub)=6​

Answer 1

Respuesta:

18

Explicación paso a paso:

n(A') = 50 => n(A) = n(U) - 50

n(B') = 40 => n(B) = n(U) - 40

n(U) = 60 => n(A) = 10; n(B) = 20

n(A^B) = 6

Hallar n(A(triangulo)B)

=n(A-B) + n(B-A) = n(A) - n(A^B) + n(B) - n(A^B)

Reemplazando

10 - 6 +20 - 6 = 18