Question

calcular "m" en:
$\sqrt{ \sqrt{ {x}^{m} } \sqrt{ {x}^{m.2} } } = {x}^{3}$
ayuda por favor urgente​

Answer 1

Respuesta:

m = 4

Explicación paso a paso:

$\sqrt{ \sqrt{ {x}^{m} } \sqrt{ {x}^{m.2} } } = {x}^{3} \\ \sqrt{ \sqrt{ {x}^{m} } \sqrt{ {x}^{2m} } } = {x}^{3} \\ \sqrt{ \sqrt{ {x}^{m}. {x}^{2m} } } = {x}^{3} \\ \sqrt[4]{ {x}^{3m} } = {x}^{3} \\ {x}^{ \frac{3m}{4} } = {x}^{3} \\ \frac{3m}{4} = 3 \\ 3m = 3 \times 4 \\ 3m = 12 \\ m = \frac{12}{3} \\ m = 4$

Answer 2

Hola!

Respuesta:

m = 4

Explicación paso a paso:

Resolviendo...

$\sqrt{ \sqrt{ {x}^{m} } \sqrt{ {x}^{m.2} } } = {x}^{3} \\ \sqrt{ {x}^{m} } \sqrt{ {x}^{m.2} } = {( {x}^{3} )}^{2} \\ \sqrt{ {x}^{m} \times {x }^{2m} } = {x}^{6} \\ {x}^{m + 2m} = {( {x}^{6}) }^{2} \\ {x}^{3m} = {x}^{12} \\ \\ a \:bases \: iguales \: los \: exponentes \: tambien \: se \: igualan : \\ \\ x = x \\ 3m = 12 \\ m = \frac{12}{3} \\ m = 4$